Drew Youngren dcy2@columbia.edu
Operation | Notation | Formula |
---|---|---|
Magnitude | $| \mathbf v |$ | $\sqrt{\sum v_i^2}$ |
Scalar Multiplication | $c \mathbf v$ | $\left\langle c v_1, \ldots, c v_n \right\rangle$ |
Vector Addition | $\mathbf v + \mathbf w$ | $\left\langle v_1 + w_1, \ldots, v_n + w_n \right\rangle$ |
Dot Product | $\mathbf v \cdot \mathbf w$ | $\sum v_i w_i$ |
Cross Product | $\mathbf v \times \mathbf w$ | $ \langle v_2 w_3 - v_3 w_2, v_3 w_1 - v_1 w_3, v_1 w_2 - v_2 w_1 \rangle $ |
There is a special vector product, or cross product in $\RR^3$ only. \[\vec v \times \vec w = \vec u\] "A vector cross a vector is a vector."
If $\vec v$ and $\vec w$ define adjacent sides of a parallelogram, the area is $|\vec v \times \vec w|$.
A line in $\RR^n$ with position $\vec p$ and direction $\vec v$ has parametric form \[ \vec r(t) = \vec p + t\,\vec v \]
Find a parametric form for the line through $(-1, 0, -1)$ and $(1, 1,1)$.
Find position and director vectors for the line with parametric equations: \[ \begin{align*} x &= t - 1 \\ y &= t /2 \\ z &= 3 - 3t \\ \end{align*} \]
Find the intersection of the line through $(0,0)$ and $(2,1)$ and the line with position $\langle 6, -1 \rangle$ and direction $\langle 4, -6 \rangle$.
Solution.
\[ t \bv{2 \\ 1} = \bv{6 \\ -1} + s \bv{4 \\ -6} \]$t = 2, s = - \frac{1}{2}$ means intersection point is $(4, 2)$.
Follow up. At what angle do these lines meet?
We could define a plane via its parametric form with a position vector and 2 direction vectors. \[\vec r(s,t) =\vec p + s \vec v + t \vec w\]
But in $\RR^3$, we can define a plane with a 1 position vector $\vec p$ and one normal vector $\vec n$ to define the plane equation.
What is a normal vector to the plane given by \[ x+2y = 16-8z \,?\] Find a point on this plane.
The distance between sets is defined as the minimum of all distances between points in the respective sets. \[ \operatorname{dist}(X,Y) = \operatorname{min}\limits_{\vec x \in X, \vec y \in Y} |\vec x - \vec y| \]
Find the distance from a position $\vec y$ to a plane with normal $\vec n$ and position $\vec p$.